Base | Representation |
---|---|
bin | 1100111100111101000110… |
… | …0110011111011001001011 |
3 | 1212102110100222202101222102 |
4 | 3033033101212133121023 |
5 | 3331312222234130233 |
6 | 50142213401144015 |
7 | 2666621340105311 |
oct | 317172146373113 |
9 | 55373328671872 |
10 | 14241333114443 |
11 | 45a07962aa4a6 |
12 | 172009578b00b |
13 | 7c3c4b586096 |
14 | 3733d9bbc0b1 |
15 | 19a6b2ddb1e8 |
hex | cf3d199f64b |
14241333114443 has 2 divisors, whose sum is σ = 14241333114444. Its totient is φ = 14241333114442.
The previous prime is 14241333114419. The next prime is 14241333114461. The reversal of 14241333114443 is 34441133314241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14241333114443 - 210 = 14241333113419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14241333114397 and 14241333114406.
It is not a weakly prime, because it can be changed into another prime (14241333114473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120666557221 + 7120666557222.
It is an arithmetic number, because the mean of its divisors is an integer number (7120666557222).
Almost surely, 214241333114443 is an apocalyptic number.
14241333114443 is a deficient number, since it is larger than the sum of its proper divisors (1).
14241333114443 is an equidigital number, since it uses as much as digits as its factorization.
14241333114443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 165888, while the sum is 38.
Adding to 14241333114443 its reverse (34441133314241), we get a palindrome (48682466428684).
The spelling of 14241333114443 in words is "fourteen trillion, two hundred forty-one billion, three hundred thirty-three million, one hundred fourteen thousand, four hundred forty-three".
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