Base | Representation |
---|---|
bin | 100000011000011001101100… |
… | …001101001111101110010011 |
3 | 200200020200022021210200011102 |
4 | 200120121230031033232103 |
5 | 122131304032244343441 |
6 | 1222520124533535015 |
7 | 41666045063215631 |
oct | 4030315415175623 |
9 | 620220267720142 |
10 | 142414341012371 |
11 | 4141764584926a |
12 | 13b80a2a7a446b |
13 | 61607cb74c32c |
14 | 2724c68824351 |
15 | 116e7cce0669b |
hex | 81866c34fb93 |
142414341012371 has 2 divisors, whose sum is σ = 142414341012372. Its totient is φ = 142414341012370.
The previous prime is 142414341012299. The next prime is 142414341012413. The reversal of 142414341012371 is 173210143414241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142414341012371 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (142414341012971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71207170506185 + 71207170506186.
It is an arithmetic number, because the mean of its divisors is an integer number (71207170506186).
Almost surely, 2142414341012371 is an apocalyptic number.
142414341012371 is a deficient number, since it is larger than the sum of its proper divisors (1).
142414341012371 is an equidigital number, since it uses as much as digits as its factorization.
142414341012371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 38.
The spelling of 142414341012371 in words is "one hundred forty-two trillion, four hundred fourteen billion, three hundred forty-one million, twelve thousand, three hundred seventy-one".
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