142420433 has 2 divisors, whose sum is σ = 142420434. Its totient is φ = 142420432.

The previous prime is 142420423. The next prime is 142420451. The reversal of 142420433 is 334024241.

142420433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81938704 + 60481729 = 9052^2 + 7777^2 .

It is an emirp because it is prime and its reverse (334024241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142420433 is a prime.

It is a super-3 number, since 3×142420433³ (a number of 25 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142420399 and 142420408.

It is not a weakly prime, because it can be changed into another prime (142420423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71210216 + 71210217.

It is an arithmetic number, because the mean of its divisors is an integer number (71210217).

Almost surely, 2^142420433 is an apocalyptic number.

It is an amenable number.

142420433 is a deficient number, since it is larger than the sum of its proper divisors (1).

142420433 is an equidigital number, since it uses as much as digits as its factorization.

142420433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 23.

The square root of 142420433 is about 11934.0032260763. The cubic root of 142420433 is about 522.2247298926.

Adding to 142420433 its reverse (334024241), we get a palindrome (476444674).

The spelling of 142420433 in words is "one hundred forty-two million, four hundred twenty thousand, four hundred thirty-three".