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14242200113 is a prime number
BaseRepresentation
bin11010100001110011…
…01011101000110001
31100202120012201200002
431100321223220301
5213132000400423
610313123435345
71012635463211
oct152071535061
940676181602
1014242200113
116049394819
122915825b55
13145c85025b
14991722241
15585526228
hex350e6ba31

14242200113 has 2 divisors, whose sum is σ = 14242200114. Its totient is φ = 14242200112.

The previous prime is 14242200103. The next prime is 14242200233. The reversal of 14242200113 is 31100224241.

14242200113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13269196864 + 973003249 = 115192^2 + 31193^2 .

It is an emirp because it is prime and its reverse (31100224241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14242200113 - 28 = 14242199857 is a prime.

It is not a weakly prime, because it can be changed into another prime (14242200103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121100056 + 7121100057.

It is an arithmetic number, because the mean of its divisors is an integer number (7121100057).

Almost surely, 214242200113 is an apocalyptic number.

It is an amenable number.

14242200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14242200113 is an equidigital number, since it uses as much as digits as its factorization.

14242200113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 14242200113 its reverse (31100224241), we get a palindrome (45342424354).

The spelling of 14242200113 in words is "fourteen billion, two hundred forty-two million, two hundred thousand, one hundred thirteen".