Base | Representation |
---|---|
bin | 11010100001111010… |
… | …01010000110001001 |
3 | 1100202121221000120221 |
4 | 31100331022012021 |
5 | 213132214030210 |
6 | 10313155150041 |
7 | 1012646306563 |
oct | 152075120611 |
9 | 40677830527 |
10 | 14243111305 |
11 | 6049957375 |
12 | 2915ba5321 |
13 | 145caabc17 |
14 | 9918bc333 |
15 | 5856561da |
hex | 350f4a189 |
14243111305 has 8 divisors (see below), whose sum is σ = 17137558152. Its totient is φ = 11363939328.
The previous prime is 14243111273. The next prime is 14243111339. The reversal of 14243111305 is 50311134241.
It can be written as a sum of positive squares in 4 ways, for example, as 1710980496 + 12532130809 = 41364^2 + 111947^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14243111305 - 25 = 14243111273 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14243111305.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3816664 + ... + 3820393.
It is an arithmetic number, because the mean of its divisors is an integer number (2142194769).
Almost surely, 214243111305 is an apocalyptic number.
It is an amenable number.
14243111305 is a deficient number, since it is larger than the sum of its proper divisors (2894446847).
14243111305 is an equidigital number, since it uses as much as digits as its factorization.
14243111305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7637435.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 14243111305 its reverse (50311134241), we get a palindrome (64554245546).
The spelling of 14243111305 in words is "fourteen billion, two hundred forty-three million, one hundred eleven thousand, three hundred five".
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