Base | Representation |
---|---|
bin | 1100111101000011110110… |
… | …0100000101011111101111 |
3 | 1212102122001020001102202121 |
4 | 3033100331210011133233 |
5 | 3331324424433022112 |
6 | 50143113223533411 |
7 | 3000014253013414 |
oct | 317207544053757 |
9 | 55378036042677 |
10 | 14243144423407 |
11 | 45a1535788759 |
12 | 17205002ba267 |
13 | 7c4179905733 |
14 | 37352c59a10b |
15 | 19a76be2a407 |
hex | cf43d9057ef |
14243144423407 has 2 divisors, whose sum is σ = 14243144423408. Its totient is φ = 14243144423406.
The previous prime is 14243144423381. The next prime is 14243144423441. The reversal of 14243144423407 is 70432444134241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14243144423407 - 27 = 14243144423279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14243144423447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121572211703 + 7121572211704.
It is an arithmetic number, because the mean of its divisors is an integer number (7121572211704).
Almost surely, 214243144423407 is an apocalyptic number.
14243144423407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14243144423407 is an equidigital number, since it uses as much as digits as its factorization.
14243144423407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1032192, while the sum is 43.
Adding to 14243144423407 its reverse (70432444134241), we get a palindrome (84675588557648).
The spelling of 14243144423407 in words is "fourteen trillion, two hundred forty-three billion, one hundred forty-four million, four hundred twenty-three thousand, four hundred seven".
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