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1424332104211 is a prime number
BaseRepresentation
bin10100101110100000110…
…011110010001000010011
312001011110011010202111201
4110232200303302020103
5141314013004313321
63010155032052031
7204622164061252
oct24564063621023
95034404122451
101424332104211
114aa068382325
121b0065b34017
13a4410961983
144cd1bdb4799
15270b43a2291
hex14ba0cf2213

1424332104211 has 2 divisors, whose sum is σ = 1424332104212. Its totient is φ = 1424332104210.

The previous prime is 1424332104187. The next prime is 1424332104227. The reversal of 1424332104211 is 1124012334241.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1424332104211 - 29 = 1424332103699 is a prime.

It is a super-2 number, since 2×14243321042112 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1424332104211.

It is not a weakly prime, because it can be changed into another prime (1424332104271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712166052105 + 712166052106.

It is an arithmetic number, because the mean of its divisors is an integer number (712166052106).

Almost surely, 21424332104211 is an apocalyptic number.

1424332104211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424332104211 is an equidigital number, since it uses as much as digits as its factorization.

1424332104211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1424332104211 its reverse (1124012334241), we get a palindrome (2548344438452).

The spelling of 1424332104211 in words is "one trillion, four hundred twenty-four billion, three hundred thirty-two million, one hundred four thousand, two hundred eleven".