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14243340112013 is a prime number
BaseRepresentation
bin1100111101000100100100…
…1110100101000010001101
31212102122112212021110001202
43033101021032211002031
53331330330032041023
650143144454115245
73000022150233215
oct317211116450215
955378485243052
1014243340112013
1145a1626196481
12172055594bb25
137c41ab3104cc
1437354a579245
1519a77e1d2128
hexcf4493a508d

14243340112013 has 2 divisors, whose sum is σ = 14243340112014. Its totient is φ = 14243340112012.

The previous prime is 14243340111977. The next prime is 14243340112019. The reversal of 14243340112013 is 31021104334241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12740994719209 + 1502345392804 = 3569453^2 + 1225702^2 .

It is a cyclic number.

It is not a de Polignac number, because 14243340112013 - 226 = 14243273003149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14243340112019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121670056006 + 7121670056007.

It is an arithmetic number, because the mean of its divisors is an integer number (7121670056007).

Almost surely, 214243340112013 is an apocalyptic number.

It is an amenable number.

14243340112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14243340112013 is an equidigital number, since it uses as much as digits as its factorization.

14243340112013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14243340112013 its reverse (31021104334241), we get a palindrome (45264444446254).

The spelling of 14243340112013 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty million, one hundred twelve thousand, thirteen".