Base | Representation |
---|---|
bin | 1100111101000100100100… |
… | …1110100101000010001101 |
3 | 1212102122112212021110001202 |
4 | 3033101021032211002031 |
5 | 3331330330032041023 |
6 | 50143144454115245 |
7 | 3000022150233215 |
oct | 317211116450215 |
9 | 55378485243052 |
10 | 14243340112013 |
11 | 45a1626196481 |
12 | 172055594bb25 |
13 | 7c41ab3104cc |
14 | 37354a579245 |
15 | 19a77e1d2128 |
hex | cf4493a508d |
14243340112013 has 2 divisors, whose sum is σ = 14243340112014. Its totient is φ = 14243340112012.
The previous prime is 14243340111977. The next prime is 14243340112019. The reversal of 14243340112013 is 31021104334241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12740994719209 + 1502345392804 = 3569453^2 + 1225702^2 .
It is a cyclic number.
It is not a de Polignac number, because 14243340112013 - 226 = 14243273003149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14243340112019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121670056006 + 7121670056007.
It is an arithmetic number, because the mean of its divisors is an integer number (7121670056007).
Almost surely, 214243340112013 is an apocalyptic number.
It is an amenable number.
14243340112013 is a deficient number, since it is larger than the sum of its proper divisors (1).
14243340112013 is an equidigital number, since it uses as much as digits as its factorization.
14243340112013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 14243340112013 its reverse (31021104334241), we get a palindrome (45264444446254).
The spelling of 14243340112013 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty million, one hundred twelve thousand, thirteen".
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