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1424434334117 is a prime number
BaseRepresentation
bin10100101110100110111…
…001110000100110100101
312001011201021111120120112
4110232212321300212211
5141314220142142432
63010213123142405
7204624545031524
oct24564671604645
95034637446515
101424434334117
114aa110057153
121b0094214a05
13a4428ba6442
144cd2b7c64bb
15270bd3477b2
hex14ba6e709a5

1424434334117 has 2 divisors, whose sum is σ = 1424434334118. Its totient is φ = 1424434334116.

The previous prime is 1424434334093. The next prime is 1424434334161. The reversal of 1424434334117 is 7114334344241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1027123467841 + 397310866276 = 1013471^2 + 630326^2 .

It is a cyclic number.

It is not a de Polignac number, because 1424434334117 - 236 = 1355714857381 is a prime.

It is a super-2 number, since 2×14244343341172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1424434334417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712217167058 + 712217167059.

It is an arithmetic number, because the mean of its divisors is an integer number (712217167059).

Almost surely, 21424434334117 is an apocalyptic number.

It is an amenable number.

1424434334117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424434334117 is an equidigital number, since it uses as much as digits as its factorization.

1424434334117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 387072, while the sum is 41.

Adding to 1424434334117 its reverse (7114334344241), we get a palindrome (8538768678358).

The spelling of 1424434334117 in words is "one trillion, four hundred twenty-four billion, four hundred thirty-four million, three hundred thirty-four thousand, one hundred seventeen".