Base | Representation |
---|---|
bin | 100000011000110101101101… |
… | …110110101101101100100011 |
3 | 200200100112222110222221111222 |
4 | 200120311231312231230203 |
5 | 122132302144424300311 |
6 | 1222542022550525255 |
7 | 42001161564443543 |
oct | 4030655566555443 |
9 | 620315873887458 |
10 | 142444433431331 |
11 | 41429388175aa9 |
12 | 13b8682866682b |
13 | 61635b60023b5 |
14 | 27264c1249323 |
15 | 117048ebd8adb |
hex | 818d6ddadb23 |
142444433431331 has 2 divisors, whose sum is σ = 142444433431332. Its totient is φ = 142444433431330.
The previous prime is 142444433431309. The next prime is 142444433431543. The reversal of 142444433431331 is 133134334444241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142444433431331 is a prime.
It is a super-2 number, since 2×1424444334313312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142444433431031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71222216715665 + 71222216715666.
It is an arithmetic number, because the mean of its divisors is an integer number (71222216715666).
Almost surely, 2142444433431331 is an apocalyptic number.
142444433431331 is a deficient number, since it is larger than the sum of its proper divisors (1).
142444433431331 is an equidigital number, since it uses as much as digits as its factorization.
142444433431331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1990656, while the sum is 44.
Adding to 142444433431331 its reverse (133134334444241), we get a palindrome (275578767875572).
The spelling of 142444433431331 in words is "one hundred forty-two trillion, four hundred forty-four billion, four hundred thirty-three million, four hundred thirty-one thousand, three hundred thirty-one".
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