Base | Representation |
---|---|
bin | 100000011000110101101101… |
… | …110110101101101111110111 |
3 | 200200100112222110222221210211 |
4 | 200120311231312231233313 |
5 | 122132302144424302133 |
6 | 1222542022550530251 |
7 | 42001161564444265 |
oct | 4030655566555767 |
9 | 620315873887724 |
10 | 142444433431543 |
11 | 41429388176181 |
12 | 13b86828666987 |
13 | 61635b6002519 |
14 | 27264c1249435 |
15 | 117048ebd8bcd |
hex | 818d6ddadbf7 |
142444433431543 has 2 divisors, whose sum is σ = 142444433431544. Its totient is φ = 142444433431542.
The previous prime is 142444433431331. The next prime is 142444433431561. The reversal of 142444433431543 is 345134334444241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142444433431543 - 29 = 142444433431031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142444433437543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71222216715771 + 71222216715772.
It is an arithmetic number, because the mean of its divisors is an integer number (71222216715772).
Almost surely, 2142444433431543 is an apocalyptic number.
142444433431543 is a deficient number, since it is larger than the sum of its proper divisors (1).
142444433431543 is an equidigital number, since it uses as much as digits as its factorization.
142444433431543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13271040, while the sum is 49.
Adding to 142444433431543 its reverse (345134334444241), we get a palindrome (487578767875784).
The spelling of 142444433431543 in words is "one hundred forty-two trillion, four hundred forty-four billion, four hundred thirty-three million, four hundred thirty-one thousand, five hundred forty-three".
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