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142444433431543 is a prime number
BaseRepresentation
bin100000011000110101101101…
…110110101101101111110111
3200200100112222110222221210211
4200120311231312231233313
5122132302144424302133
61222542022550530251
742001161564444265
oct4030655566555767
9620315873887724
10142444433431543
1141429388176181
1213b86828666987
1361635b6002519
1427264c1249435
15117048ebd8bcd
hex818d6ddadbf7

142444433431543 has 2 divisors, whose sum is σ = 142444433431544. Its totient is φ = 142444433431542.

The previous prime is 142444433431331. The next prime is 142444433431561. The reversal of 142444433431543 is 345134334444241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142444433431543 - 29 = 142444433431031 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142444433437543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71222216715771 + 71222216715772.

It is an arithmetic number, because the mean of its divisors is an integer number (71222216715772).

Almost surely, 2142444433431543 is an apocalyptic number.

142444433431543 is a deficient number, since it is larger than the sum of its proper divisors (1).

142444433431543 is an equidigital number, since it uses as much as digits as its factorization.

142444433431543 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13271040, while the sum is 49.

Adding to 142444433431543 its reverse (345134334444241), we get a palindrome (487578767875784).

The spelling of 142444433431543 in words is "one hundred forty-two trillion, four hundred forty-four billion, four hundred thirty-three million, four hundred thirty-one thousand, five hundred forty-three".