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14244450254053 is a prime number
BaseRepresentation
bin1100111101001000101101…
…1001011011110011100101
31212102202102020012111122121
43033102023121123303211
53331340113231112203
650143450552225541
73000061520260015
oct317221331336345
955382366174577
1014244450254053
1145a20458a8638
12172080569b2b1
137c43273025a6
14373613b97c45
1519a7e68bd0bd
hexcf48b65bce5

14244450254053 has 2 divisors, whose sum is σ = 14244450254054. Its totient is φ = 14244450254052.

The previous prime is 14244450254003. The next prime is 14244450254081. The reversal of 14244450254053 is 35045205444241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9842036388804 + 4402413865249 = 3137202^2 + 2098193^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14244450254053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14244450254003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122225127026 + 7122225127027.

It is an arithmetic number, because the mean of its divisors is an integer number (7122225127027).

Almost surely, 214244450254053 is an apocalyptic number.

It is an amenable number.

14244450254053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14244450254053 is an equidigital number, since it uses as much as digits as its factorization.

14244450254053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536000, while the sum is 43.

Adding to 14244450254053 its reverse (35045205444241), we get a palindrome (49289655698294).

The spelling of 14244450254053 in words is "fourteen trillion, two hundred forty-four billion, four hundred fifty million, two hundred fifty-four thousand, fifty-three".