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1424635015117 is a prime number
BaseRepresentation
bin10100101110110010110…
…111010010111111001101
312001012020021010020011011
4110232302313102333031
5141320123030440432
63010245052325221
7204632532553366
oct24566267227715
95035207106134
101424635015117
114aa203364816
121b012b473811
13a445b63b6b2
144cd4a304b6d
15270d0c88847
hex14bb2dd2fcd

1424635015117 has 2 divisors, whose sum is σ = 1424635015118. Its totient is φ = 1424635015116.

The previous prime is 1424635015061. The next prime is 1424635015129. The reversal of 1424635015117 is 7115105364241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1402924171401 + 21710843716 = 1184451^2 + 147346^2 .

It is a cyclic number.

It is not a de Polignac number, because 1424635015117 - 27 = 1424635014989 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1424635015117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1424635015717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712317507558 + 712317507559.

It is an arithmetic number, because the mean of its divisors is an integer number (712317507559).

Almost surely, 21424635015117 is an apocalyptic number.

It is an amenable number.

1424635015117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424635015117 is an equidigital number, since it uses as much as digits as its factorization.

1424635015117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 40.

The spelling of 1424635015117 in words is "one trillion, four hundred twenty-four billion, six hundred thirty-five million, fifteen thousand, one hundred seventeen".