Base | Representation |
---|---|
bin | 1000010010101110000… |
… | …0010100000011010001 |
3 | 111121201112210111010211 |
4 | 2010223200110003101 |
5 | 4313231213434133 |
6 | 145240313524121 |
7 | 13202246264032 |
oct | 2045340240321 |
9 | 447645714124 |
10 | 142463811793 |
11 | 55467120436 |
12 | 2373aa13641 |
13 | 105851608b4 |
14 | 6c7693ca89 |
15 | 3a8c19ebcd |
hex | 212b8140d1 |
142463811793 has 2 divisors, whose sum is σ = 142463811794. Its totient is φ = 142463811792.
The previous prime is 142463811781. The next prime is 142463811863. The reversal of 142463811793 is 397118364241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 141219627264 + 1244184529 = 375792^2 + 35273^2 .
It is a cyclic number.
It is not a de Polignac number, because 142463811793 - 221 = 142461714641 is a prime.
It is a super-3 number, since 3×1424638117933 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (142463811713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71231905896 + 71231905897.
It is an arithmetic number, because the mean of its divisors is an integer number (71231905897).
Almost surely, 2142463811793 is an apocalyptic number.
It is an amenable number.
142463811793 is a deficient number, since it is larger than the sum of its proper divisors (1).
142463811793 is an equidigital number, since it uses as much as digits as its factorization.
142463811793 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 870912, while the sum is 49.
The spelling of 142463811793 in words is "one hundred forty-two billion, four hundred sixty-three million, eight hundred eleven thousand, seven hundred ninety-three".
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