1425113 has 2 divisors, whose sum is σ = 1425114. Its totient is φ = 1425112.

The previous prime is 1425097. The next prime is 1425121. The reversal of 1425113 is 3115241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1373584 + 51529 = 1172^2 + 227^2 .

It is an emirp because it is prime and its reverse (3115241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1425113 - 2⁴ = 1425097 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1425091 and 1425100.

It is not a weakly prime, because it can be changed into another prime (1425913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712556 + 712557.

It is an arithmetic number, because the mean of its divisors is an integer number (712557).

2^1425113 is an apocalyptic number.

It is an amenable number.

1425113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425113 is an equidigital number, since it uses as much as digits as its factorization.

1425113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120, while the sum is 17.

The square root of 1425113 is about 1193.7809681847. The cubic root of 1425113 is about 112.5338301550.

The spelling of 1425113 in words is "one million, four hundred twenty-five thousand, one hundred thirteen".