Base | Representation |
---|---|
bin | 10100101111001111010… |
… | …111100000010100101101 |
3 | 12001020110120221120110211 |
4 | 110233033113200110231 |
5 | 141322112441023042 |
6 | 3010404334102421 |
7 | 204650430335026 |
oct | 24571727402455 |
9 | 5036416846424 |
10 | 1425113220397 |
11 | 4aa429295499 |
12 | 1b024364aa11 |
13 | a45067324b9 |
14 | 4cd93a25c4d |
15 | 2710cc49017 |
hex | 14bcf5e052d |
1425113220397 has 2 divisors, whose sum is σ = 1425113220398. Its totient is φ = 1425113220396.
The previous prime is 1425113220379. The next prime is 1425113220451. The reversal of 1425113220397 is 7930223115241.
Together with previous prime (1425113220379) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1319601290121 + 105511930276 = 1148739^2 + 324826^2 .
It is a cyclic number.
It is not a de Polignac number, because 1425113220397 - 27 = 1425113220269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1425113220337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712556610198 + 712556610199.
It is an arithmetic number, because the mean of its divisors is an integer number (712556610199).
Almost surely, 21425113220397 is an apocalyptic number.
It is an amenable number.
1425113220397 is a deficient number, since it is larger than the sum of its proper divisors (1).
1425113220397 is an equidigital number, since it uses as much as digits as its factorization.
1425113220397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 40.
The spelling of 1425113220397 in words is "one trillion, four hundred twenty-five billion, one hundred thirteen million, two hundred twenty thousand, three hundred ninety-seven".
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