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1425113220397 is a prime number
BaseRepresentation
bin10100101111001111010…
…111100000010100101101
312001020110120221120110211
4110233033113200110231
5141322112441023042
63010404334102421
7204650430335026
oct24571727402455
95036416846424
101425113220397
114aa429295499
121b024364aa11
13a45067324b9
144cd93a25c4d
152710cc49017
hex14bcf5e052d

1425113220397 has 2 divisors, whose sum is σ = 1425113220398. Its totient is φ = 1425113220396.

The previous prime is 1425113220379. The next prime is 1425113220451. The reversal of 1425113220397 is 7930223115241.

Together with previous prime (1425113220379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1319601290121 + 105511930276 = 1148739^2 + 324826^2 .

It is a cyclic number.

It is not a de Polignac number, because 1425113220397 - 27 = 1425113220269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1425113220337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712556610198 + 712556610199.

It is an arithmetic number, because the mean of its divisors is an integer number (712556610199).

Almost surely, 21425113220397 is an apocalyptic number.

It is an amenable number.

1425113220397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425113220397 is an equidigital number, since it uses as much as digits as its factorization.

1425113220397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 40.

The spelling of 1425113220397 in words is "one trillion, four hundred twenty-five billion, one hundred thirteen million, two hundred twenty thousand, three hundred ninety-seven".