Base | Representation |
---|---|
bin | 1100111101100111001111… |
… | …0010100100110100000011 |
3 | 1212110112120021102022210201 |
4 | 3033121303302210310003 |
5 | 3332003403344012310 |
6 | 50151324015310031 |
7 | 3000501544112254 |
oct | 317316362446403 |
9 | 55415507368721 |
10 | 14252644125955 |
11 | 45a55700528a4 |
12 | 172231181b317 |
13 | 7c5031a655c1 |
14 | 373b900cab2b |
15 | 19ab25e11e3a |
hex | cf673ca4d03 |
14252644125955 has 32 divisors (see below), whose sum is σ = 17275104000000. Its totient is φ = 11287744215552.
The previous prime is 14252644125949. The next prime is 14252644126001. The reversal of 14252644125955 is 55952144625241.
It is a cyclic number.
It is not a de Polignac number, because 14252644125955 - 213 = 14252644117763 is a prime.
It is a super-2 number, since 2×142526441259552 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14252644125896 and 14252644125905.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2851096546 + ... + 2851101544.
It is an arithmetic number, because the mean of its divisors is an integer number (539847000000).
Almost surely, 214252644125955 is an apocalyptic number.
14252644125955 is a deficient number, since it is larger than the sum of its proper divisors (3022459874045).
14252644125955 is a wasteful number, since it uses less digits than its factorization.
14252644125955 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10123.
The product of its digits is 17280000, while the sum is 55.
The spelling of 14252644125955 in words is "fourteen trillion, two hundred fifty-two billion, six hundred forty-four million, one hundred twenty-five thousand, nine hundred fifty-five".
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