Base | Representation |
---|---|
bin | 1100111101101001000010… |
… | …0001100111110011010011 |
3 | 1212110120210212120021220011 |
4 | 3033122100201213303103 |
5 | 3332010400303033021 |
6 | 50151443520255351 |
7 | 3000516516624226 |
oct | 317322041476323 |
9 | 55416725507804 |
10 | 14253126221011 |
11 | 45a579819aa67 |
12 | 1722427171557 |
13 | 7c50aa8bba52 |
14 | 373bd81415bd |
15 | 19ab533dede1 |
hex | cf690867cd3 |
14253126221011 has 2 divisors, whose sum is σ = 14253126221012. Its totient is φ = 14253126221010.
The previous prime is 14253126220997. The next prime is 14253126221017. The reversal of 14253126221011 is 11012262135241.
It is a strong prime.
It is an emirp because it is prime and its reverse (11012262135241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14253126221011 - 221 = 14253124123859 is a prime.
It is not a weakly prime, because it can be changed into another prime (14253126221017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126563110505 + 7126563110506.
It is an arithmetic number, because the mean of its divisors is an integer number (7126563110506).
Almost surely, 214253126221011 is an apocalyptic number.
14253126221011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14253126221011 is an equidigital number, since it uses as much as digits as its factorization.
14253126221011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 14253126221011 its reverse (11012262135241), we get a palindrome (25265388356252).
The spelling of 14253126221011 in words is "fourteen trillion, two hundred fifty-three billion, one hundred twenty-six million, two hundred twenty-one thousand, eleven".
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