1425365513035 has 4 divisors (see below), whose sum is σ = 1710438615648. Its totient is φ = 1140292410424.

The previous prime is 1425365513021. The next prime is 1425365513063. The reversal of 1425365513035 is 5303155635241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1425365513035 - 2⁵ = 1425365513003 is a prime.

It is a super-2 number, since 2×1425365513035² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1425365512982 and 1425365513000.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142536551299 + ... + 142536551308.

It is an arithmetic number, because the mean of its divisors is an integer number (427609653912).

Almost surely, 2^{1425365513035} is an apocalyptic number.

1425365513035 is a deficient number, since it is larger than the sum of its proper divisors (285073102613).

1425365513035 is an equidigital number, since it uses as much as digits as its factorization.

1425365513035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 285073102612.

The product of its (nonzero) digits is 810000, while the sum is 43.

The spelling of 1425365513035 in words is "one trillion, four hundred twenty-five billion, three hundred sixty-five million, five hundred thirteen thousand, thirty-five".