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1425405410531 is a prime number
BaseRepresentation
bin10100101111100000110…
…010000111110011100011
312001021012221202100222122
4110233200302013303203
5141323212241114111
63010453332454455
7204660606036224
oct24574062076343
95037187670878
101425405410531
114aa569215243
121b030547a42b
13a455212757b
144cdc076524b
1527128713cdb
hex14be0c87ce3

1425405410531 has 2 divisors, whose sum is σ = 1425405410532. Its totient is φ = 1425405410530.

The previous prime is 1425405410521. The next prime is 1425405410617. The reversal of 1425405410531 is 1350145045241.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1425405410531 - 222 = 1425401216227 is a prime.

It is a super-3 number, since 3×14254054105313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1425405410491 and 1425405410500.

It is not a weakly prime, because it can be changed into another prime (1425405410521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712702705265 + 712702705266.

It is an arithmetic number, because the mean of its divisors is an integer number (712702705266).

Almost surely, 21425405410531 is an apocalyptic number.

1425405410531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425405410531 is an equidigital number, since it uses as much as digits as its factorization.

1425405410531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48000, while the sum is 35.

The spelling of 1425405410531 in words is "one trillion, four hundred twenty-five billion, four hundred five million, four hundred ten thousand, five hundred thirty-one".