142543345241 has 4 divisors (see below), whose sum is σ = 155501831184. Its totient is φ = 129584859300.

The previous prime is 142543345223. The next prime is 142543345249.

142543345241 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142543345241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142543345195 and 142543345204.

It is not an unprimeable number, because it can be changed into a prime (142543345249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6479242955 + ... + 6479242976.

It is an arithmetic number, because the mean of its divisors is an integer number (38875457796).

Almost surely, 2^142543345241 is an apocalyptic number.

142543345241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

142543345241 is a deficient number, since it is larger than the sum of its proper divisors (12958485943).

142543345241 is a wasteful number, since it uses less digits than its factorization.

142543345241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12958485942.

The product of its digits is 230400, while the sum is 38.

It can be divided in two parts, 142543 and 345241, that added together give a palindrome (487784).

The spelling of 142543345241 in words is "one hundred forty-two billion, five hundred forty-three million, three hundred forty-five thousand, two hundred forty-one".