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14254643360497 is a prime number
BaseRepresentation
bin1100111101101110101011…
…1101000011001011110001
31212110201201121022222000111
43033123222331003023301
53332022002200013442
650152254234021321
73000602231245351
oct317335275031361
955421647288014
1014254643360497
1145a63a6617351
12172278b277841
137c5290002417
14373cdd826b61
1519abe16c2b17
hexcf6eaf432f1

14254643360497 has 2 divisors, whose sum is σ = 14254643360498. Its totient is φ = 14254643360496.

The previous prime is 14254643360479. The next prime is 14254643360533. The reversal of 14254643360497 is 79406334645241.

Together with previous prime (14254643360479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11877838387776 + 2376804972721 = 3446424^2 + 1541689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14254643360497 is a prime.

It is a super-2 number, since 2×142546433604972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14254643360597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7127321680248 + 7127321680249.

It is an arithmetic number, because the mean of its divisors is an integer number (7127321680249).

Almost surely, 214254643360497 is an apocalyptic number.

It is an amenable number.

14254643360497 is a deficient number, since it is larger than the sum of its proper divisors (1).

14254643360497 is an equidigital number, since it uses as much as digits as its factorization.

14254643360497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52254720, while the sum is 58.

The spelling of 14254643360497 in words is "fourteen trillion, two hundred fifty-four billion, six hundred forty-three million, three hundred sixty thousand, four hundred ninety-seven".