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14254643360533 is a prime number
BaseRepresentation
bin1100111101101110101011…
…1101000011001100010101
31212110201201121022222001211
43033123222331003030111
53332022002200014113
650152254234021421
73000602231245432
oct317335275031425
955421647288054
1014254643360533
1145a63a6617384
12172278b277871
137c5290002444
14373cdd826b89
1519abe16c2b3d
hexcf6eaf43315

14254643360533 has 2 divisors, whose sum is σ = 14254643360534. Its totient is φ = 14254643360532.

The previous prime is 14254643360497. The next prime is 14254643360539. The reversal of 14254643360533 is 33506334645241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11379712864689 + 2874930495844 = 3373383^2 + 1695562^2 .

It is a cyclic number.

It is not a de Polignac number, because 14254643360533 - 229 = 14254106489621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14254643360539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7127321680266 + 7127321680267.

It is an arithmetic number, because the mean of its divisors is an integer number (7127321680267).

Almost surely, 214254643360533 is an apocalyptic number.

It is an amenable number.

14254643360533 is a deficient number, since it is larger than the sum of its proper divisors (1).

14254643360533 is an equidigital number, since it uses as much as digits as its factorization.

14254643360533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9331200, while the sum is 49.

The spelling of 14254643360533 in words is "fourteen trillion, two hundred fifty-four billion, six hundred forty-three million, three hundred sixty thousand, five hundred thirty-three".