Base | Representation |
---|---|
bin | 1000010011000010110… |
… | …1000100110101111111 |
3 | 111121221121221022111010 |
4 | 2010300231010311333 |
5 | 4313421031342310 |
6 | 145253111330303 |
7 | 13204355606532 |
oct | 2046055046577 |
9 | 447847838433 |
10 | 142551043455 |
11 | 55501390917 |
12 | 23764080993 |
13 | 1059a253772 |
14 | 6c84368a19 |
15 | 3a94b81320 |
hex | 2130b44d7f |
142551043455 has 32 divisors (see below), whose sum is σ = 229780355328. Its totient is φ = 75463027200.
The previous prime is 142551043421. The next prime is 142551043469. The reversal of 142551043455 is 554340155241.
142551043455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 142551043455 - 26 = 142551043391 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1063815 + ... + 1190295.
It is an arithmetic number, because the mean of its divisors is an integer number (7180636104).
Almost surely, 2142551043455 is an apocalyptic number.
142551043455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
142551043455 is a deficient number, since it is larger than the sum of its proper divisors (87229311873).
142551043455 is a wasteful number, since it uses less digits than its factorization.
142551043455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127047.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 142551043455 its reverse (554340155241), we get a palindrome (696891198696).
The spelling of 142551043455 in words is "one hundred forty-two billion, five hundred fifty-one million, forty-three thousand, four hundred fifty-five".
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