14255140140011 has 4 divisors (see below), whose sum is σ = 14586655027032. Its totient is φ = 13923625252992.

The previous prime is 14255140139897. The next prime is 14255140140023. The reversal of 14255140140011 is 11004104155241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14255140140011 is a prime.

It is a super-2 number, since 2×14255140140011² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14255140140611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165757443446 + ... + 165757443531.

It is an arithmetic number, because the mean of its divisors is an integer number (3646663756758).

Almost surely, 2^{14255140140011} is an apocalyptic number.

14255140140011 is a deficient number, since it is larger than the sum of its proper divisors (331514887021).

14255140140011 is an equidigital number, since it uses as much as digits as its factorization.

14255140140011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 331514887020.

The product of its (nonzero) digits is 3200, while the sum is 29.

Adding to 14255140140011 its reverse (11004104155241), we get a palindrome (25259244295252).

The spelling of 14255140140011 in words is "fourteen trillion, two hundred fifty-five billion, one hundred forty million, one hundred forty thousand, eleven".