Base | Representation |
---|---|
bin | 100000011010100001011101… |
… | …100000111110011101000101 |
3 | 200200202121121010010000012112 |
4 | 200122201131200332131011 |
5 | 122141201113043224331 |
6 | 1223111114440430405 |
7 | 42012425520203003 |
oct | 4032413540763505 |
9 | 620677533100175 |
10 | 142560123414341 |
11 | 41473455150606 |
12 | 13ba5134a78405 |
13 | 61714922a0a49 |
14 | 272bd37dbba73 |
15 | 11734b15cc32b |
hex | 81a85d83e745 |
142560123414341 has 2 divisors, whose sum is σ = 142560123414342. Its totient is φ = 142560123414340.
The previous prime is 142560123414329. The next prime is 142560123414349. The reversal of 142560123414341 is 143414321065241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78162467630116 + 64397655784225 = 8840954^2 + 8024815^2 .
It is a cyclic number.
It is not a de Polignac number, because 142560123414341 - 214 = 142560123397957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142560123414349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71280061707170 + 71280061707171.
It is an arithmetic number, because the mean of its divisors is an integer number (71280061707171).
Almost surely, 2142560123414341 is an apocalyptic number.
It is an amenable number.
142560123414341 is a deficient number, since it is larger than the sum of its proper divisors (1).
142560123414341 is an equidigital number, since it uses as much as digits as its factorization.
142560123414341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 41.
Adding to 142560123414341 its reverse (143414321065241), we get a palindrome (285974444479582).
The spelling of 142560123414341 in words is "one hundred forty-two trillion, five hundred sixty billion, one hundred twenty-three million, four hundred fourteen thousand, three hundred forty-one".
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