Search a number
-
+
1426118536393 is a prime number
BaseRepresentation
bin10100110000001011010…
…010011110110011001001
312001100001122121220202121
4110300023102132303021
5141331142321131033
63011052205331241
7205014355356325
oct24601322366311
95040048556677
101426118536393
114aa8a480a261
121b0484266b21
13a4636ab1235
144d04b358985
152716b12a62d
hex14c0b49ecc9

1426118536393 has 2 divisors, whose sum is σ = 1426118536394. Its totient is φ = 1426118536392.

The previous prime is 1426118536391. The next prime is 1426118536397. The reversal of 1426118536393 is 3936358116241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1178086647609 + 248031888784 = 1085397^2 + 498028^2 .

It is a cyclic number.

It is not a de Polignac number, because 1426118536393 - 21 = 1426118536391 is a prime.

Together with 1426118536391, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1426118536393.

It is not a weakly prime, because it can be changed into another prime (1426118536391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713059268196 + 713059268197.

It is an arithmetic number, because the mean of its divisors is an integer number (713059268197).

Almost surely, 21426118536393 is an apocalyptic number.

It is an amenable number.

1426118536393 is a deficient number, since it is larger than the sum of its proper divisors (1).

1426118536393 is an equidigital number, since it uses as much as digits as its factorization.

1426118536393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2799360, while the sum is 52.

The spelling of 1426118536393 in words is "one trillion, four hundred twenty-six billion, one hundred eighteen million, five hundred thirty-six thousand, three hundred ninety-three".