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142630035553021 is a prime number
BaseRepresentation
bin100000011011100010100100…
…100110100111101011111101
3200201000022001102010122000011
4200123202210212213223331
5122143322303100144041
61223203200032303221
742020452146445132
oct4033424446475375
9621008042118004
10142630035553021
11414a0070792115
1213bb67a63a1b11
136177c54464a43
14273148b082589
151175204134e81
hex81b8a49a7afd

142630035553021 has 2 divisors, whose sum is σ = 142630035553022. Its totient is φ = 142630035553020.

The previous prime is 142630035553003. The next prime is 142630035553037. The reversal of 142630035553021 is 120355530036241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140517576788121 + 2112458764900 = 11854011^2 + 1453430^2 .

It is an emirp because it is prime and its reverse (120355530036241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142630035553021 - 215 = 142630035520253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142630035553051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71315017776510 + 71315017776511.

It is an arithmetic number, because the mean of its divisors is an integer number (71315017776511).

Almost surely, 2142630035553021 is an apocalyptic number.

It is an amenable number.

142630035553021 is a deficient number, since it is larger than the sum of its proper divisors (1).

142630035553021 is an equidigital number, since it uses as much as digits as its factorization.

142630035553021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 142630035553021 its reverse (120355530036241), we get a palindrome (262985565589262).

The spelling of 142630035553021 in words is "one hundred forty-two trillion, six hundred thirty billion, thirty-five million, five hundred fifty-three thousand, twenty-one".