Search a number
-
+
1426742513341 is a prime number
BaseRepresentation
bin10100110000110000011…
…110110000111010111101
312001101200010202020012221
4110300300132300322331
5141333432040411331
63011234135325341
7205036003160155
oct24606036607275
95041603666187
101426742513341
11500094a54392
121b0619220851
13a4706153472
144d0aa183765
15271a5cd2711
hex14c307b0ebd

1426742513341 has 2 divisors, whose sum is σ = 1426742513342. Its totient is φ = 1426742513340.

The previous prime is 1426742513309. The next prime is 1426742513359. The reversal of 1426742513341 is 1433152476241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1227710536441 + 199031976900 = 1108021^2 + 446130^2 .

It is an emirp because it is prime and its reverse (1433152476241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1426742513341 - 25 = 1426742513309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1426742513041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713371256670 + 713371256671.

It is an arithmetic number, because the mean of its divisors is an integer number (713371256671).

Almost surely, 21426742513341 is an apocalyptic number.

It is an amenable number.

1426742513341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1426742513341 is an equidigital number, since it uses as much as digits as its factorization.

1426742513341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 483840, while the sum is 43.

Adding to 1426742513341 its reverse (1433152476241), we get a palindrome (2859894989582).

The spelling of 1426742513341 in words is "one trillion, four hundred twenty-six billion, seven hundred forty-two million, five hundred thirteen thousand, three hundred forty-one".