Base | Representation |
---|---|
bin | 10100110001011010101… |
… | …011101100101111110111 |
3 | 12001110111111001002001212 |
4 | 110301122223230233313 |
5 | 141341404320002231 |
6 | 3011432311112035 |
7 | 205062361311614 |
oct | 24613253545767 |
9 | 5043444032055 |
10 | 1427450547191 |
11 | 500418690729 |
12 | 1b079637261b |
13 | a47b9a464c6 |
14 | 4d13620d50b |
15 | 271e804042b |
hex | 14c5aaecbf7 |
1427450547191 has 4 divisors (see below), whose sum is σ = 1427508899232. Its totient is φ = 1427392195152.
The previous prime is 1427450547181. The next prime is 1427450547209. The reversal of 1427450547191 is 1917450547241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1427450547191 - 218 = 1427450285047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1427450547181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29139311 + ... + 29188256.
It is an arithmetic number, because the mean of its divisors is an integer number (356877224808).
Almost surely, 21427450547191 is an apocalyptic number.
1427450547191 is a deficient number, since it is larger than the sum of its proper divisors (58352041).
1427450547191 is an equidigital number, since it uses as much as digits as its factorization.
1427450547191 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58352040.
The product of its (nonzero) digits is 1411200, while the sum is 50.
Adding to 1427450547191 its sum of digits (50), we get a palindrome (1427450547241).
The spelling of 1427450547191 in words is "one trillion, four hundred twenty-seven billion, four hundred fifty million, five hundred forty-seven thousand, one hundred ninety-one".
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