Base | Representation |
---|---|
bin | 10100110010010000010… |
… | …111100011110101011001 |
3 | 12001112211020211212211220 |
4 | 110302100113203311121 |
5 | 141400230404044330 |
6 | 3012101524042253 |
7 | 205123606124025 |
oct | 24622027436531 |
9 | 5045736755756 |
10 | 1428351237465 |
11 | 500840044659 |
12 | 1b09a7b33389 |
13 | a4901522129 |
14 | 4d1bdaa9385 |
15 | 2724c156710 |
hex | 14c905e3d59 |
1428351237465 has 8 divisors (see below), whose sum is σ = 2285361979968. Its totient is φ = 761787326640.
The previous prime is 1428351237449. The next prime is 1428351237503. The reversal of 1428351237465 is 5647321538241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1428351237465 - 24 = 1428351237449 is a prime.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47611707901 + ... + 47611707930.
It is an arithmetic number, because the mean of its divisors is an integer number (285670247496).
Almost surely, 21428351237465 is an apocalyptic number.
1428351237465 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1428351237465 is a deficient number, since it is larger than the sum of its proper divisors (857010742503).
1428351237465 is an equidigital number, since it uses as much as digits as its factorization.
1428351237465 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95223415839.
The product of its digits is 4838400, while the sum is 51.
The spelling of 1428351237465 in words is "one trillion, four hundred twenty-eight billion, three hundred fifty-one million, two hundred thirty-seven thousand, four hundred sixty-five".
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