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1428573000161 is a prime number
BaseRepresentation
bin10100110010011101100…
…101100001000111100001
312001120101201010121002002
4110302131211201013201
5141401204142001121
63012135525133345
7205132241101346
oct24623545410741
95046351117062
101428573000161
1150094424120a
121b0a4a25a255
13a4938458c68
144d2013147cd
152726185de0b
hex14c9d9611e1

1428573000161 has 2 divisors, whose sum is σ = 1428573000162. Its totient is φ = 1428573000160.

The previous prime is 1428573000143. The next prime is 1428573000163. The reversal of 1428573000161 is 1610003758241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1251400195600 + 177172804561 = 1118660^2 + 420919^2 .

It is a cyclic number.

It is not a de Polignac number, because 1428573000161 - 210 = 1428572999137 is a prime.

Together with 1428573000163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1428573000163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 714286500080 + 714286500081.

It is an arithmetic number, because the mean of its divisors is an integer number (714286500081).

Almost surely, 21428573000161 is an apocalyptic number.

It is an amenable number.

1428573000161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1428573000161 is an equidigital number, since it uses as much as digits as its factorization.

1428573000161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 1428573000161 in words is "one trillion, four hundred twenty-eight billion, five hundred seventy-three million, one hundred sixty-one", and thus it is an aban number.