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14300113 is a prime number
BaseRepresentation
bin110110100011…
…001111010001
3222220112001211
4312203033101
512130100423
61230300121
7232356202
oct66431721
928815054
1014300113
118087983
124957641
132c68c09
141c835a9
1513c710d
hexda33d1

14300113 has 2 divisors, whose sum is σ = 14300114. Its totient is φ = 14300112.

The previous prime is 14300101. The next prime is 14300119. The reversal of 14300113 is 31100341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10870209 + 3429904 = 3297^2 + 1852^2 .

It is a cyclic number.

It is not a de Polignac number, because 14300113 - 25 = 14300081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14300093 and 14300102.

It is not a weakly prime, because it can be changed into another prime (14300119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150056 + 7150057.

It is an arithmetic number, because the mean of its divisors is an integer number (7150057).

Almost surely, 214300113 is an apocalyptic number.

It is an amenable number.

14300113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300113 is an equidigital number, since it uses as much as digits as its factorization.

14300113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 14300113 is about 3781.5490212346. The cubic root of 14300113 is about 242.7242436319.

Adding to 14300113 its reverse (31100341), we get a palindrome (45400454).

The spelling of 14300113 in words is "fourteen million, three hundred thousand, one hundred thirteen".