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14300132311 is a prime number
BaseRepresentation
bin11010101000101101…
…01011001111010111
31100220121012222201001
431110112223033113
5213241313213221
610322553244131
71014241055563
oct152426531727
940817188631
1014300132311
116079063073
122931103647
13146b854c6a
149992c26a3
1558a66b391
hex3545ab3d7

14300132311 has 2 divisors, whose sum is σ = 14300132312. Its totient is φ = 14300132310.

The previous prime is 14300132291. The next prime is 14300132323. The reversal of 14300132311 is 11323100341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14300132311 - 29 = 14300131799 is a prime.

It is a super-2 number, since 2×143001323112 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14300132111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150066155 + 7150066156.

It is an arithmetic number, because the mean of its divisors is an integer number (7150066156).

Almost surely, 214300132311 is an apocalyptic number.

14300132311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300132311 is an equidigital number, since it uses as much as digits as its factorization.

14300132311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 14300132311 its reverse (11323100341), we get a palindrome (25623232652).

It can be divided in two parts, 14300 and 132311, that added together give a triangular number (146611 = T541).

The spelling of 14300132311 in words is "fourteen billion, three hundred million, one hundred thirty-two thousand, three hundred eleven".