Base | Representation |
---|---|
bin | 11010101000101110… |
… | …00001101110110001 |
3 | 1100220121101200001222 |
4 | 31110113001232301 |
5 | 213241324140213 |
6 | 10322555234425 |
7 | 1014241621265 |
oct | 152427015661 |
9 | 40817350058 |
10 | 14300224433 |
11 | 6079116300 |
12 | 2931148a15 |
13 | 146b887b81 |
14 | 9993080a5 |
15 | 58a688808 |
hex | 3545c1bb1 |
14300224433 has 12 divisors (see below), whose sum is σ = 15721819344. Its totient is φ = 12997399800.
The previous prime is 14300224409. The next prime is 14300224487. The reversal of 14300224433 is 33442200341.
14300224433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14300224433 - 26 = 14300224369 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14300224633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 727310 + ... + 746712.
It is an arithmetic number, because the mean of its divisors is an integer number (1310151612).
Almost surely, 214300224433 is an apocalyptic number.
It is an amenable number.
14300224433 is a deficient number, since it is larger than the sum of its proper divisors (1421594911).
14300224433 is a wasteful number, since it uses less digits than its factorization.
14300224433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25516 (or 25505 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 14300224433 its reverse (33442200341), we get a palindrome (47742424774).
The spelling of 14300224433 in words is "fourteen billion, three hundred million, two hundred twenty-four thousand, four hundred thirty-three".
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