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1430034434131 is a prime number
BaseRepresentation
bin10100110011110100101…
…100011100100001010011
312001201011120002010121011
4110303310230130201103
5141412202303343011
63012540532511351
7205213405062652
oct24636454344123
95051146063534
101430034434131
11501524180186
121b119777b557
13a4b0c1672a4
144d2dd459199
15272e9cdb621
hex14cf4b1c853

1430034434131 has 2 divisors, whose sum is σ = 1430034434132. Its totient is φ = 1430034434130.

The previous prime is 1430034434107. The next prime is 1430034434173. The reversal of 1430034434131 is 1314344300341.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1314344300341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1430034434131 - 223 = 1430026045523 is a prime.

It is a super-2 number, since 2×14300344341312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1430034434093 and 1430034434102.

It is not a weakly prime, because it can be changed into another prime (1430034432131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715017217065 + 715017217066.

It is an arithmetic number, because the mean of its divisors is an integer number (715017217066).

Almost surely, 21430034434131 is an apocalyptic number.

1430034434131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1430034434131 is an equidigital number, since it uses as much as digits as its factorization.

1430034434131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1430034434131 its reverse (1314344300341), we get a palindrome (2744378734472).

The spelling of 1430034434131 in words is "one trillion, four hundred thirty billion, thirty-four million, four hundred thirty-four thousand, one hundred thirty-one".