1430044320211 has 4 divisors (see below), whose sum is σ = 1540047729472. Its totient is φ = 1320040910952.

The previous prime is 1430044320209. The next prime is 1430044320301. The reversal of 1430044320211 is 1120234400341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1430044320211 - 2¹ = 1430044320209 is a prime.

It is a super-2 number, since 2×1430044320211² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1430044320311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55001704611 + ... + 55001704636.

It is an arithmetic number, because the mean of its divisors is an integer number (385011932368).

Almost surely, 2^{1430044320211} is an apocalyptic number.

1430044320211 is a deficient number, since it is larger than the sum of its proper divisors (110003409261).

1430044320211 is a wasteful number, since it uses less digits than its factorization.

1430044320211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110003409260.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1430044320211 its reverse (1120234400341), we get a palindrome (2550278720552).

The spelling of 1430044320211 in words is "one trillion, four hundred thirty billion, forty-four million, three hundred twenty thousand, two hundred eleven".