Base | Representation |
---|---|
bin | 10100110011111001011… |
… | …001011100110000010001 |
3 | 12001201101001112222200210 |
4 | 110303321121130300101 |
5 | 141412333003343213 |
6 | 3012552432034333 |
7 | 205215353552331 |
oct | 24637131346021 |
9 | 5051331488623 |
10 | 1430113340433 |
11 | 5015647746a8 |
12 | 1b11ba0929a9 |
13 | a4b226038cb |
14 | 4d309b190c1 |
15 | 27301bc60c3 |
hex | 14cf965cc11 |
1430113340433 has 8 divisors (see below), whose sum is σ = 1916697672928. Its totient is φ = 948468950784.
The previous prime is 1430113340419. The next prime is 1430113340441. The reversal of 1430113340433 is 3340433110341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-1430113340433 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1430113340433.
It is not an unprimeable number, because it can be changed into a prime (1430113340483) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1234985035 + ... + 1234986192.
It is an arithmetic number, because the mean of its divisors is an integer number (239587209116).
Almost surely, 21430113340433 is an apocalyptic number.
It is an amenable number.
1430113340433 is a deficient number, since it is larger than the sum of its proper divisors (486584332495).
1430113340433 is a wasteful number, since it uses less digits than its factorization.
1430113340433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2469971423.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 1430113340433 its reverse (3340433110341), we get a palindrome (4770546450774).
The spelling of 1430113340433 in words is "one trillion, four hundred thirty billion, one hundred thirteen million, three hundred forty thousand, four hundred thirty-three".
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