Base | Representation |
---|---|
bin | 100000100001001111000011… |
… | …110111100001101000100111 |
3 | 200202101201020102100021002021 |
4 | 200201033003313201220213 |
5 | 122221230312414233221 |
6 | 1224103043003524011 |
7 | 42060645446306665 |
oct | 4041170367415047 |
9 | 622351212307067 |
10 | 143021402102311 |
11 | 41631043a21187 |
12 | 1405a60a229607 |
13 | 61a5b25251865 |
14 | 27463b67a7c35 |
15 | 11804acb09041 |
hex | 8213c3de1a27 |
143021402102311 has 4 divisors (see below), whose sum is σ = 143047260253224. Its totient is φ = 142995543951400.
The previous prime is 143021402102281. The next prime is 143021402102333. The reversal of 143021402102311 is 113201204120341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143021402102311 - 25 = 143021402102279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143021402102011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12929067160 + ... + 12929078221.
It is an arithmetic number, because the mean of its divisors is an integer number (35761815063306).
Almost surely, 2143021402102311 is an apocalyptic number.
143021402102311 is a deficient number, since it is larger than the sum of its proper divisors (25858150913).
143021402102311 is an equidigital number, since it uses as much as digits as its factorization.
143021402102311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25858150912.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 143021402102311 its reverse (113201204120341), we get a palindrome (256222606222652).
The spelling of 143021402102311 in words is "one hundred forty-three trillion, twenty-one billion, four hundred two million, one hundred two thousand, three hundred eleven".
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