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1430301342013 is a prime number
BaseRepresentation
bin10100110100000100100…
…110100111100100111101
312001201212011022110101021
4110310010212213210331
5141413224120421023
63013023225344141
7205223125545025
oct24640446474475
95051764273337
101430301342013
11501650902005
121b1251038051
13a4b5254984b
144d326a96a85
152731346035d
hex14d049a793d

1430301342013 has 2 divisors, whose sum is σ = 1430301342014. Its totient is φ = 1430301342012.

The previous prime is 1430301342007. The next prime is 1430301342023. The reversal of 1430301342013 is 3102431030341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1252523582244 + 177777759769 = 1119162^2 + 421637^2 .

It is a cyclic number.

It is not a de Polignac number, because 1430301342013 - 29 = 1430301341501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1430301342023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715150671006 + 715150671007.

It is an arithmetic number, because the mean of its divisors is an integer number (715150671007).

Almost surely, 21430301342013 is an apocalyptic number.

It is an amenable number.

1430301342013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1430301342013 is an equidigital number, since it uses as much as digits as its factorization.

1430301342013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1430301342013 its reverse (3102431030341), we get a palindrome (4532732372354).

The spelling of 1430301342013 in words is "one trillion, four hundred thirty billion, three hundred one million, three hundred forty-two thousand, thirteen".