1430302947841 has 4 divisors (see below), whose sum is σ = 1430412975684. Its totient is φ = 1430192920000.

The previous prime is 1430302947833. The next prime is 1430302947859. The reversal of 1430302947841 is 1487492030341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 480449991025 + 949852956816 = 693145^2 + 974604^2 .

It is a cyclic number.

It is not a de Polignac number, because 1430302947841 - 2³ = 1430302947833 is a prime.

It is a super-2 number, since 2×1430302947841² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1430302947791 and 1430302947800.

It is not an unprimeable number, because it can be changed into a prime (1430302947641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54994420 + ... + 55020421.

It is an arithmetic number, because the mean of its divisors is an integer number (357603243921).

Almost surely, 2^{1430302947841} is an apocalyptic number.

It is an amenable number.

1430302947841 is a deficient number, since it is larger than the sum of its proper divisors (110027843).

1430302947841 is a wasteful number, since it uses less digits than its factorization.

1430302947841 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110027842.

The product of its (nonzero) digits is 580608, while the sum is 46.

The spelling of 1430302947841 in words is "one trillion, four hundred thirty billion, three hundred two million, nine hundred forty-seven thousand, eight hundred forty-one".