Base | Representation |
---|---|
bin | 11010101001000011… |
… | …10100110111110001 |
3 | 1100220210201111100120 |
4 | 31110201310313301 |
5 | 213243040232340 |
6 | 10323140040453 |
7 | 1014304651545 |
oct | 152441646761 |
9 | 40823644316 |
10 | 14303055345 |
11 | 607a77a1a7 |
12 | 2932093129 |
13 | 146c339577 |
14 | 999843a25 |
15 | 58aa474d0 |
hex | 354874df1 |
14303055345 has 64 divisors (see below), whose sum is σ = 24236858880. Its totient is φ = 7192184832.
The previous prime is 14303055313. The next prime is 14303055407. The reversal of 14303055345 is 54355030341.
It is not a de Polignac number, because 14303055345 - 25 = 14303055313 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3268579 + ... + 3272951.
It is an arithmetic number, because the mean of its divisors is an integer number (378700920).
Almost surely, 214303055345 is an apocalyptic number.
14303055345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14303055345 is a deficient number, since it is larger than the sum of its proper divisors (9933803535).
14303055345 is a wasteful number, since it uses less digits than its factorization.
14303055345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4586.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 14303055345 its reverse (54355030341), we get a palindrome (68658085686).
The spelling of 14303055345 in words is "fourteen billion, three hundred three million, fifty-five thousand, three hundred forty-five".
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