Base | Representation |
---|---|
bin | 1101000000100011001100… |
… | …1101101110001000110111 |
3 | 1212122100210122200002111002 |
4 | 3100020303031232020313 |
5 | 3333320222141034201 |
6 | 50230430435033515 |
7 | 3004236105555464 |
oct | 320106315561067 |
9 | 55570718602432 |
10 | 14303100330551 |
11 | 4614a0228a13a |
12 | 173005343b89b |
13 | 7c9a13195176 |
14 | 3763b925266b |
15 | 19c0ca86d76b |
hex | d023336e237 |
14303100330551 has 8 divisors (see below), whose sum is σ = 14452692343824. Its totient is φ = 14153551937280.
The previous prime is 14303100330527. The next prime is 14303100330569. The reversal of 14303100330551 is 15503300130341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14303100330551 - 210 = 14303100329527 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14303100335551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10245560 + ... + 11557581.
It is an arithmetic number, because the mean of its divisors is an integer number (1806586542978).
Almost surely, 214303100330551 is an apocalyptic number.
14303100330551 is a deficient number, since it is larger than the sum of its proper divisors (149592013273).
14303100330551 is an equidigital number, since it uses as much as digits as its factorization.
14303100330551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21810001.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 14303100330551 its reverse (15503300130341), we get a palindrome (29806400460892).
The spelling of 14303100330551 in words is "fourteen trillion, three hundred three billion, one hundred million, three hundred thirty thousand, five hundred fifty-one".
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