Base | Representation |
---|---|
bin | 10100110100000101001… |
… | …100100110110010001010 |
3 | 12001201212212001101111021 |
4 | 110310011030212302022 |
5 | 141413234143101414 |
6 | 3013024223023054 |
7 | 205223306311525 |
oct | 24640514466212 |
9 | 5051785041437 |
10 | 1430311300234 |
11 | 501656493843 |
12 | 1b125443aa8a |
13 | a4b5462539b |
14 | 4d328129bbc |
15 | 2731427ac24 |
hex | 14d05326c8a |
1430311300234 has 32 divisors (see below), whose sum is σ = 2189150361216. Its totient is φ = 700744504320.
The previous prime is 1430311300211. The next prime is 1430311300247. The reversal of 1430311300234 is 4320031130341.
It is a junction number, because it is equal to n+sod(n) for n = 1430311300199 and 1430311300208.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151079169 + ... + 151088635.
It is an arithmetic number, because the mean of its divisors is an integer number (68410948788).
Almost surely, 21430311300234 is an apocalyptic number.
1430311300234 is a deficient number, since it is larger than the sum of its proper divisors (758839060982).
1430311300234 is a wasteful number, since it uses less digits than its factorization.
1430311300234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17230.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1430311300234 its reverse (4320031130341), we get a palindrome (5750342430575).
The spelling of 1430311300234 in words is "one trillion, four hundred thirty billion, three hundred eleven million, three hundred thousand, two hundred thirty-four".
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