Base | Representation |
---|---|
bin | 10100110100000101001… |
… | …100110000100000001100 |
3 | 12001201212212010102002201 |
4 | 110310011030300200030 |
5 | 141413234200340134 |
6 | 3013024223531244 |
7 | 205223306535556 |
oct | 24640514604014 |
9 | 5051785112081 |
10 | 1430311340044 |
11 | 501656510744 |
12 | 1b1254459b24 |
13 | a4b5463a542 |
14 | 4d32813a4d6 |
15 | 27314287914 |
hex | 14d0533080c |
1430311340044 has 24 divisors (see below), whose sum is σ = 2569451312960. Its totient is φ = 696430410624.
The previous prime is 1430311340033. The next prime is 1430311340149. The reversal of 1430311340044 is 4400431130341.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1430311339994 and 1430311340021.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30978999 + ... + 31025134.
Almost surely, 21430311340044 is an apocalyptic number.
It is an amenable number.
1430311340044 is a deficient number, since it is larger than the sum of its proper divisors (1139139972916).
1430311340044 is a wasteful number, since it uses less digits than its factorization.
1430311340044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62004289 (or 62004287 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1430311340044 its reverse (4400431130341), we get a palindrome (5830742470385).
The spelling of 1430311340044 in words is "one trillion, four hundred thirty billion, three hundred eleven million, three hundred forty thousand, forty-four".
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