14303123241041 has 4 divisors (see below), whose sum is σ = 14537600671284. Its totient is φ = 14068645810800.

The previous prime is 14303123240993. The next prime is 14303123241103. The reversal of 14303123241041 is 14014232130341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1445054026816 + 12858069214225 = 1202104^2 + 3585815^2 .

It is a cyclic number.

It is not a de Polignac number, because 14303123241041 - 2⁶ = 14303123240977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14303123240995 and 14303123241013.

It is not an unprimeable number, because it can be changed into a prime (14303123241541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117238715030 + ... + 117238715151.

It is an arithmetic number, because the mean of its divisors is an integer number (3634400167821).

Almost surely, 2^{14303123241041} is an apocalyptic number.

It is an amenable number.

14303123241041 is a deficient number, since it is larger than the sum of its proper divisors (234477430243).

14303123241041 is an equidigital number, since it uses as much as digits as its factorization.

14303123241041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234477430242.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14303123241041 its reverse (14014232130341), we get a palindrome (28317355371382).

The spelling of 14303123241041 in words is "fourteen trillion, three hundred three billion, one hundred twenty-three million, two hundred forty-one thousand, forty-one".