Base | Representation |
---|---|
bin | 10100110100000110010… |
… | …111111010011010010111 |
3 | 12001201221020012100022201 |
4 | 110310012113322122113 |
5 | 141413304221311211 |
6 | 3013030210105331 |
7 | 205223636152165 |
oct | 24640627723227 |
9 | 5051836170281 |
10 | 1430331041431 |
11 | 501666647686 |
12 | 1b125ab7b247 |
13 | a4b58747a76 |
14 | 4d32a9c8235 |
15 | 27315d7a0c1 |
hex | 14d065fa697 |
1430331041431 has 2 divisors, whose sum is σ = 1430331041432. Its totient is φ = 1430331041430.
The previous prime is 1430331041369. The next prime is 1430331041449. The reversal of 1430331041431 is 1341401330341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1430331041431 - 27 = 1430331041303 is a prime.
It is a super-2 number, since 2×14303310414312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1430331041431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430331048431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715165520715 + 715165520716.
It is an arithmetic number, because the mean of its divisors is an integer number (715165520716).
Almost surely, 21430331041431 is an apocalyptic number.
1430331041431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430331041431 is an equidigital number, since it uses as much as digits as its factorization.
1430331041431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1430331041431 its reverse (1341401330341), we get a palindrome (2771732371772).
The spelling of 1430331041431 in words is "one trillion, four hundred thirty billion, three hundred thirty-one million, forty-one thousand, four hundred thirty-one".
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