Base | Representation |
---|---|
bin | 10100110100000110011… |
… | …011110000101011001111 |
3 | 12001201221022002120222211 |
4 | 110310012123300223033 |
5 | 141413310001101002 |
6 | 3013030243451251 |
7 | 205223650553041 |
oct | 24640633605317 |
9 | 5051838076884 |
10 | 1430332050127 |
11 | 501667176512 |
12 | 1b125b386b27 |
13 | a4b58a0bc26 |
14 | 4d32ababa91 |
15 | 27315ec8dd7 |
hex | 14d066f0acf |
1430332050127 has 2 divisors, whose sum is σ = 1430332050128. Its totient is φ = 1430332050126.
The previous prime is 1430332050109. The next prime is 1430332050151. The reversal of 1430332050127 is 7210502330341.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1430332050127 is a prime.
It is a super-2 number, since 2×14303320501272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430332050197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715166025063 + 715166025064.
It is an arithmetic number, because the mean of its divisors is an integer number (715166025064).
Almost surely, 21430332050127 is an apocalyptic number.
1430332050127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430332050127 is an equidigital number, since it uses as much as digits as its factorization.
1430332050127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 1430332050127 its reverse (7210502330341), we get a palindrome (8640834380468).
The spelling of 1430332050127 in words is "one trillion, four hundred thirty billion, three hundred thirty-two million, fifty thousand, one hundred twenty-seven".
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