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14303444104399 is a prime number
BaseRepresentation
bin1101000000100100011110…
…1101000111010011001111
31212122101200121112121112211
43100021013231013103033
53333321423142320044
650230524515211251
73004250451601552
oct320110755072317
955571617477484
1014303444104399
11461506934155a
12173012a5a6b27
137c9a6947b448
1437640cb7c699
1519c0eab27634
hexd0247b474cf

14303444104399 has 2 divisors, whose sum is σ = 14303444104400. Its totient is φ = 14303444104398.

The previous prime is 14303444104387. The next prime is 14303444104487. The reversal of 14303444104399 is 99340144430341.

14303444104399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14303444104399 - 217 = 14303443973327 is a prime.

It is a super-2 number, since 2×143034441043992 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14303444104199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151722052199 + 7151722052200.

It is an arithmetic number, because the mean of its divisors is an integer number (7151722052200).

Almost surely, 214303444104399 is an apocalyptic number.

14303444104399 is a deficient number, since it is larger than the sum of its proper divisors (1).

14303444104399 is an equidigital number, since it uses as much as digits as its factorization.

14303444104399 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 49.

The spelling of 14303444104399 in words is "fourteen trillion, three hundred three billion, four hundred forty-four million, one hundred four thousand, three hundred ninety-nine".