Base | Representation |
---|---|
bin | 1101000000100100011110… |
… | …1101000111010011001111 |
3 | 1212122101200121112121112211 |
4 | 3100021013231013103033 |
5 | 3333321423142320044 |
6 | 50230524515211251 |
7 | 3004250451601552 |
oct | 320110755072317 |
9 | 55571617477484 |
10 | 14303444104399 |
11 | 461506934155a |
12 | 173012a5a6b27 |
13 | 7c9a6947b448 |
14 | 37640cb7c699 |
15 | 19c0eab27634 |
hex | d0247b474cf |
14303444104399 has 2 divisors, whose sum is σ = 14303444104400. Its totient is φ = 14303444104398.
The previous prime is 14303444104387. The next prime is 14303444104487. The reversal of 14303444104399 is 99340144430341.
14303444104399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14303444104399 - 217 = 14303443973327 is a prime.
It is a super-2 number, since 2×143034441043992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14303444104199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151722052199 + 7151722052200.
It is an arithmetic number, because the mean of its divisors is an integer number (7151722052200).
Almost surely, 214303444104399 is an apocalyptic number.
14303444104399 is a deficient number, since it is larger than the sum of its proper divisors (1).
14303444104399 is an equidigital number, since it uses as much as digits as its factorization.
14303444104399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2239488, while the sum is 49.
The spelling of 14303444104399 in words is "fourteen trillion, three hundred three billion, four hundred forty-four million, one hundred four thousand, three hundred ninety-nine".
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