Base | Representation |
---|---|
bin | 1000010100110110011… |
… | …1000010100011000101 |
3 | 111200012102110200102102 |
4 | 2011031213002203011 |
5 | 4320414204003303 |
6 | 145413153521445 |
7 | 13222364641403 |
oct | 2051547024305 |
9 | 450172420372 |
10 | 143036000453 |
11 | 55730103225 |
12 | 2387a573285 |
13 | 1064686c778 |
14 | 6ccc926473 |
15 | 3ac2527288 |
hex | 214d9c28c5 |
143036000453 has 2 divisors, whose sum is σ = 143036000454. Its totient is φ = 143036000452.
The previous prime is 143036000449. The next prime is 143036000483. The reversal of 143036000453 is 354000630341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97204897729 + 45831102724 = 311777^2 + 214082^2 .
It is a cyclic number.
It is not a de Polignac number, because 143036000453 - 22 = 143036000449 is a prime.
It is a super-3 number, since 3×1430360004533 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143036000483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71518000226 + 71518000227.
It is an arithmetic number, because the mean of its divisors is an integer number (71518000227).
Almost surely, 2143036000453 is an apocalyptic number.
It is an amenable number.
143036000453 is a deficient number, since it is larger than the sum of its proper divisors (1).
143036000453 is an equidigital number, since it uses as much as digits as its factorization.
143036000453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 143036000453 its reverse (354000630341), we get a palindrome (497036630794).
The spelling of 143036000453 in words is "one hundred forty-three billion, thirty-six million, four hundred fifty-three", and thus it is an aban number.
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